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General discussionSolve the Maths Puzzle(114 posts)(114 posts)
(114 posts)
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This is my favourite topic
Posted January 29, 2016
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REDVWIN: That's what is commonly known as a short-circuit. As Ohm's Law clearly states, Intensity equals to Voltage divided by Resistance, if a Resistance is Zero, theorically Intensity should tend to infinite but as this isn't possible, in real world terms it necesarilly needs to be superior to Zero as well.

I am so rusty in maths but I will try to make a simple puzzle for you to solve:

I have a total of 48 socks in my drawer. 1/4 are red, 1/3 blue and the rest white. I am looking for the least movements needed to guarantee obtaining a matching pair if I pull out just one sock at a time.

REDVWIN
2 pulls, obviously.
Just look in the drawer and grab a matching pair.
(I actually had the answer, but bookwyrm beat me to it)
Post edited January 29, 2016 by zeogold
Posted January 29, 2016
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Bookwyrm627: To guarantee a matching pair of socks, you would need to pull 4 socks. 3 pulls could result in 3 different colors of sock, and the 4th pull would have to match one of those initial 3.
I was thinking that, but then I thought that was far too easy an answer.. XD
Posted January 29, 2016
Ok. Next math puzzle, please! :)

REDVWIN
Posted January 29, 2016
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REDVWIN: That's what is commonly known as a short-circuit. As Ohm's Law clearly states, Intensity equals to Voltage divided by Resistance, if a Resistance is Zero, theorically Intensity should tend to infinite but as this isn't possible, in real world terms it necesarilly needs to be superior to Zero as well.
I thought about this, but then thought it's too easy and there must be more to it...

Anyway since the next puzzle is up for grabs I'll, take it. Just give me some time to write it.
Posted January 29, 2016
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REDVWIN: That's what is commonly known as a short-circuit. As Ohm's Law clearly states, Intensity equals to Voltage divided by Resistance, if a Resistance is Zero, theorically Intensity should tend to infinite but as this isn't possible, in real world terms it necesarilly needs to be superior to Zero as well.
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ZFR: I thought about this, but then thought it's too easy and there must be more to it...

Anyway since the next puzzle is up for grabs I'll, take it. Just give me some time to write it.
Me too as there are superconductors involved but I needed to answer something convincing. ;P

REDVWIN
Posted January 29, 2016
3 camel merchants (no, this puzzle has nothing to do with camels, or merchants, but since my first two were about them, might as well include them here) had their houses close together an a small empty lake next to them. They decided to fill it with water.

The first day, the first one put 20 tons of water into it.
The next day, the socond one put 25 tons of water into it, till it was full.

The third one said "Since it's full already, how about I give you two cash instead of my share. How does 450$ sound?" The other two agreed that it was a fair share.

"That's 225$ for each of us," said the first.
"No way!" said the second. "We'll split it proportionally to the amount of water we put. You take 200$ and 250$ is for me."

They kept arguing till they decided to have a judge settle the matter for them. The judge after hearing their story said "You're both wrong. The fair way of splitting the money would be..."

What's the fair way?

HINT: it is indeed neither 225-225 nor 200-250.

You need to give some explanation to your answer. Also, this is strictly maths, no tricks. So nothing along the lines of "the judge takes 450$ as his fees and leaves them nothing."
Post edited January 29, 2016 by ZFR
Posted January 29, 2016
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ZFR: What's the fair way?
I think I see where this one is going.. but I'm struggling to work out the fair share based on that..

*ponders some more*
Posted January 29, 2016
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REDVWIN: That's what is commonly known as a short-circuit. As Ohm's Law clearly states, Intensity equals to Voltage divided by Resistance, if a Resistance is Zero, theorically Intensity should tend to infinite but as this isn't possible, in real world terms it necesarilly needs to be superior to Zero as well.
I'll count this as the correct answer.

(The tricky part of the problem is that, when you try to work it out mathematically, you have to divide by zero.)
Posted January 30, 2016
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ZFR:
Way I see it, each should have added 15 tons of water, so the third one offered $450 for his 15 tons of water. Since the first added 20 and the second 25, the first added 5 tons towards the third's share and the second 10 tons, so first should get $150 and second $300.

(Still no puzzle to add though. But you have nice ones. Or, if this is correct, passing the turn to adaliabooks, being first post.)
Posted January 30, 2016
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Cavalary: Way I see it, each should have added 15 tons of water, so the third one offered $450 for his 15 tons of water. Since the first added 20 and the second 25, the first added 5 tons towards the third's share and the second 10 tons, so first should get $150 and second $300.
Precisely.

This by the way, means the first one would get even less than had he agreed to the second one's terms. Moral of the story: learn maths before arguing.
Posted January 30, 2016
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ZFR:
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Cavalary: Way I see it, each should have added 15 tons of water, so the third one offered $450 for his 15 tons of water. Since the first added 20 and the second 25, the first added 5 tons towards the third's share and the second 10 tons, so first should get $150 and second $300.

(Still no puzzle to add though. But you have nice ones. Or, if this is correct, passing the turn to adaliabooks, being first post.)
Ah, I was on the wrong track then. Good call :)

I'd take a turn, but I can't think of any math's puzzles (or even none maths puzzles)
Posted January 30, 2016
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Cavalary: Way I see it, each should have added 15 tons of water, so the third one offered $450 for his 15 tons of water. Since the first added 20 and the second 25, the first added 5 tons towards the third's share and the second 10 tons, so first should get $150 and second $300.

(Still no puzzle to add though. But you have nice ones. Or, if this is correct, passing the turn to adaliabooks, being first post.)
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adaliabooks: Ah, I was on the wrong track then. Good call :)
Just out of curiosity, what track were you on?
Posted January 30, 2016
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adaliabooks: Ah, I was on the wrong track then. Good call :)
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ZFR: Just out of curiosity, what track were you on?
I thought this:

The next day, the socond one put 25 tons of water into it, till it was full.
Was the important bit and the second one only used part of the 25 tonnes to fill the lake, but I couldn't see any other info in the puzzle that would tell me how big the lake was.
Posted January 30, 2016
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adaliabooks: I thought this:

The next day, the socond one put 25 tons of water into it, till it was full.
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adaliabooks: Was the important bit and the second one only used part of the 25 tonnes to fill the lake, but I couldn't see any other info in the puzzle that would tell me how big the lake was.
Ah, bit of my mistake then, should've worded it differently.

Anyway, next puzzle up for grabs. If no one has anything in a day or two, I'll see if I can come up with anything. But I'd rather do a bit of solving.
Posted January 30, 2016
Here's one I posted in another topic:

Take a look at the following Wikipedia article:
https://en.wikipedia.org/w/index.php?title=Steinhaus%E2%80%93Moser_notation&oldid=685894192

The article defines a number called Moser's article. Your task, if you choose to accept it, is to tell me what the least significant digit (that is, the rightmost digit) of Moser's number is. (For example, the least significant digit of 45,723 is 3.)
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General discussionSolve the Maths Puzzle(114 posts)(114 posts)
(114 posts)